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> The Math Thread
Enzd
post Apr 13 2011, 09:34 PM
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I don't use it, but some do. SO PUT IT HERE.

This post has been edited by Enzd: Apr 13 2011, 09:35 PM


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DustyHaru
post Apr 13 2011, 10:24 PM
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e^iπ + 1 = 0

I know not math, but this is apparently a special thing.
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Elnendil
post Apr 17 2011, 12:09 AM
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I've seen it before, not far enough in to know its relevance. Is that the formula though?

http://www.wolframalpha.com/input/?i=e^%28i*n%29%2B1

This post has been edited by Elnendil: Apr 17 2011, 12:37 AM


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Walrus
post Apr 17 2011, 01:17 AM
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:/ Haven't you people ever heard of complex variables before?


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DustyHaru
post Apr 17 2011, 04:45 AM
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QUOTE(Elnendil @ Apr 16 2011, 08:09 PM) *

I've seen it before, not far enough in to know its relevance. Is that the formula though?

http://www.wolframalpha.com/input/?i=e^%28i*n%29%2B1


I think so.

QUOTE(Walrus @ Apr 16 2011, 09:17 PM) *

:/ Haven't you people ever heard of complex variables before?


nope.
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Raijinili
post Apr 17 2011, 05:04 AM
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e ^ (pi * i) + 1 = 0

Where z is a complex number, e^z is defined as
\sum_{n=0}^{\infinity} z^n / n!

Thus, where x is a real number, e^(ix) is thus defined as
\sum_{n=0}^{\infinity} i^n x^n / n!

Let's also define sine and cosine:
cos(x) := \sum_{n=0}^{\infinity} i^(2n) x^(2n) / (2n)!
sin(x) := \sum_{n=0}^{\infinity} i^(2n+1) x^(2n+1) / (2n+1)!

Or, simplified:
cos(x) := \sum_{n=0}^{\infinity} (-1)^n x^(2n) / (2n)!
sin(x) := \sum_{n=0}^{\infinity} i (-1)^n x^(2n+1) / (2n+1)!

So really, e^(ix) = cos(x) + i sin(x). Let x = pi. Then cos(pi) is -1, and sin(pi) = 0. So e^(i pi) = -1, so e^(i pi) + 1 = 0, which is kind of neat because we have addition, multiplication, exponentiation, and =, as well as 0, 1, pi, e, and i.


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Elnendil
post Apr 17 2011, 11:59 PM
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QUOTE(Walrus @ Apr 16 2011, 08:17 PM) *

:/ Haven't you people ever heard of complex variables before?

Uh, yes. I just haven't had any courses based on them. You think that they taught deeper meaning concepts of complex variables in high school? Lolno, they didn't.


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Raijinili
post Apr 18 2011, 05:49 AM
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so defensive


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Elnendil
post Apr 20 2011, 01:19 PM
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Maybe I just had a bad day, I dunno.

Looking over some geometric proofs, one of them is discussing some constructable number, sqrt(4+sqrt(7+sqrt(2))). The proof that such a number is irrational I thought was clever. First you prove that the square root of 2 is irrational. Then you have r equal that number and simply solve for the square root of 2, assuming that r is a rational number. You find a contradiction there.

The geometric one is to show that a collapsing compass is mathematically equivalent to the modern compass by proving that you can copy circles using only a collapsing compass, something it cannot easily do unlike the modern compass. You use radii of circles as triangle side lengths and show that many triangles are congruent, and thus their angles are congruent. A bit time consuming but clever.

This post has been edited by Elnendil: Apr 23 2011, 02:24 PM


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